Theory

Cushion vs Wall PhysicsImpulse, Peak Force & Contact Time

Momentum & CollisionsImpulse

Introduction

Impulse measures the total change of momentum delivered during a collision: it equals the net force integrated over the contact time, or equivalently the product of average force and duration. Two collisions can share an identical impulse while producing wildly different peak forces, the distinguishing variable is how long the contact lasts. A brief, rigid impact concentrates the momentum change into a short interval and drives the peak force high; a soft, extended contact spreads the same momentum change over a longer interval and keeps the peak force low.

This distinction drives a remarkable range of engineering decisions. Helmet liners, crumple zones, gymnastic mats, and baseball-glove pull-back technique all exploit the same underlying trade-off: accept a longer contact time to suppress peak force, without needing to alter the impulse at all. The simulator places two parallel scenarios side by side, a ball rebounding from a rigid wall in the top lane and the same ball rebounding from a compliant cushion in the bottom lane, so the force-time curves for both can be compared directly on a shared graph.

Most people expect the harder surface to feel "more impactful" but assume the difference is about total energy. The Impulse readout contradicts that instinct: at m = 0.5 kg, v = 8.0 m/s, both the Wall Peak F readout and the Cushion Peak F readout are derived from the same J = 8.00 N·s, yet the wall registers 1256.6 N against the cushion's 62.8 N. The impulse is shared; the peak forces differ by a factor of 20.


The Physics Explained

A completed run of the Cushion vs Wall simulator, showing both force-time curves on the shared graph with equal shaded areas but very different peak heights.

For an elastic rebound, where the ball reverses direction at the same speed, the total momentum change is 2mv. This quantity defines the impulse J regardless of what surface the ball strikes: J = 2·m·v. With m = 0.5 kg and v = 8.0 m/s the simulator's Impulse readout shows 8.00 N·s for both the wall lane and the cushion lane simultaneously, because both collisions are elastic rebounds at the same mass and speed.

The force is not constant during contact. The simulator models each contact as a half-sine pulse: F(t) = Fpeak·sin(π·t/Δt) over the interval 0 ≤ t ≤ Δt. Integrating this pulse over the contact time returns exactly J, confirming the impulse-momentum link. The peak of the pulse is Fpeak = (π/2)·J/Δt. Because J is fixed, doubling Δt exactly halves Fpeak: the peak force is inversely proportional to contact time.

With wall contact time set to 0.010 s and cushion contact time set to 0.200 s, the contact-time ratio is 20. The Force Ratio readout shows 20.00, matching the analytic prediction. Wall Peak F reads 1256.6 N; Cushion Peak F reads 62.8 N. The force-time graph in the secondary panel draws both half-sine curves with shaded areas beneath them: the areas are visually equal (both equal J = 8.00 N·s), but the wall curve reaches more than twenty times the height of the cushion curve.

Changing mass or speed shifts both peak forces by the same factor, so the Force Ratio readout remains pinned to the contact-time ratio. Setting m = 2.0 kg and v = 8.0 m/s raises J to 32.00 N·s and scales both peaks upward proportionally; the ratio stays at 20.00. Only adjusting the wall contact time or cushion contact time independently will change the ratio, because that alters the denominator of the peak-force formula for one lane without touching the other.


Key Equations

Impulse (elastic rebound) J = 2·m·v

For a ball that reverses direction elastically, the momentum changes from +mv to −mv, so the magnitude of the change is 2mv. With m = 0.5 kg and v = 8.0 m/s: J = 2·0.5·8.0 = 8.00 N·s. The Impulse readout in the simulator shows 8.00 N·s at those slider values, confirming the formula before either ball has moved.

Peak force (half-sine pulse) Fpeak = (π/2)·J/Δt

Integrating a half-sine pulse F(t) = Fpeak·sin(π·t/Δt) from t = 0 to t = Δt yields exactly J, so Fpeak = (π/2)·J/Δt. For the wall at default settings: Fpeak = (π/2)·8.00/0.010 ≈ 1256.6 N. For the cushion: Fpeak = (π/2)·8.00/0.200 ≈ 62.8 N. Both values match the Wall Peak F and Cushion Peak F readouts at m = 0.5 kg, v = 8.0 m/s.

Force ratio Fwall/Fcush = Δtcush/Δtwall

Because both peak forces share the same J in the numerator, the ratio simplifies to the inverse ratio of contact times. With Δtwall = 0.010 s and Δtcush = 0.200 s: ratio = 0.200/0.010 = 20.00. The Force Ratio readout displays 20.00 at those settings, and it updates live as either contact-time slider is moved, a direct display of the inverse relationship without any recalculation of J.

Impulse-momentum theorem J = Δp = m·Δv

In general form, impulse equals the change in momentum. For the elastic rebound case here, Δv = 2v, so J = m·(2v) = 2mv, recovering the first equation. This theorem guarantees that no matter how the force-time curve is shaped, sharp wall pulse or broad cushion pulse, the area beneath it must equal the fixed momentum change. The simulator's shaded graph areas make this constraint visible: both shaded regions have equal area regardless of their very different heights and widths.


Key Variables

Symbol Name Unit Meaning
mBall masskgInertial mass of the rebounding ball
vImpact speedm/sSpeed of the ball just before contact; same for both lanes
JImpulseN·sTotal momentum change; equals 2mv for an elastic rebound
ΔtContact timesDuration of the force pulse; set independently for wall and cushion
FpeakPeak forceNMaximum force during the half-sine contact pulse; equals (π/2)·J/Δt
Fwall/FcushForce ratiodimensionlessRatio of wall to cushion peak force; equals Δtcush/Δtwall

Real World Examples

The Cushion vs Wall simulator set up with default parameters, showing the two lanes before the run begins.

Why do sports helmets use foam padding instead of a rigid shell alone?

A rigid shell alone stops the head quickly, short contact time, enormous peak force. Foam padding inside the helmet compresses during impact, extending the contact time from roughly 5 ms to 15–20 ms for a typical helmet liner. Because impulse equals the change in momentum and the momentum change is fixed by the head's mass and impact speed, spreading that same impulse over a longer interval reduces the peak force by the same factor.

In the simulator with m = 0.5 kg, v = 8.0 m/s, wall contact time 0.010 s and cushion contact time 0.20 s, the Impulse readout holds at 8.00 N·s for both lanes while the Wall Peak F readout shows 1256.6 N against the Cushion Peak F of 62.8 N, a factor of 20, matching the contact-time ratio exactly. Helmet engineers target that ratio: a 3× increase in crush distance reliably delivers a 3× reduction in the peak deceleration force transmitted to the skull, which is what determines concussion risk.

How do crumple zones in cars reduce injury without changing crash momentum?

In a frontal collision the car must absorb a fixed change in momentum regardless of whether the front end is rigid or crushable. A rigid bumper stops the vehicle in perhaps 30 ms; a crumple zone engineered to deform progressively can extend that to 90–120 ms. The impulse, the area under the force-time curve, is identical in both cases because it equals the momentum change. What changes is the peak of that curve: with contact time tripled, peak force on the passenger cell drops to one-third.

The simulator captures this geometry directly. Setting m = 0.5 kg, v = 8.0 m/s, wall contact time 0.010 s and cushion contact time 0.030 s puts the Force Ratio readout at exactly 3.00, because the ratio equals the contact-time ratio when impulse is shared. Automotive crash standards specify a minimum crush length precisely to guarantee that ratio stays above a threshold that keeps peak deceleration below the injury limit.

Why do fielders in cricket and baseball pull their hands back when catching?

A ball arriving at 35 m/s carries a fixed momentum relative to the stationary glove. Whether the fielder catches it with locked wrists or pulls back, the ball's momentum change is the same and the impulse delivered to the hands is identical. The pull-back motion extends the stopping distance and therefore the contact time, exactly the cushion effect. A catch completed over 0.08 s instead of 0.02 s cuts the peak force on the palm by a factor of four.

The simulator's force-time graph shows this concretely: with m = 0.5 kg, v = 8.0 m/s, shortening the cushion contact time from 0.20 s to 0.05 s quadruples the Cushion Peak F readout from 62.8 N to 251.3 N while the Impulse readout remains fixed at 8.00 N·s. Fielding coaches teach the pull-back not as style but as injury prevention grounded directly in the impulse-momentum theorem.


Further Reading