Theory

Pressure vs Depth PhysicsHydrostatic Pressure & Fluid Columns

Fluid MechanicsPressure

Introduction

The pressure inside a still liquid is set by one thing only: how far below the free surface you are. Sink a sensor into a tank and its reading climbs steadily as it descends, in exact proportion to depth and to the density of the liquid around it. That simple rule, written P = ρ · g · h, is the foundation of hydrostatics and the reason a diver at 10 m feels roughly twice the squeeze of a diver at 5 m.

The relationship matters wherever a fluid is stored or confined. Dam walls, submarine hulls, storage tanks, municipal water towers, hydraulic brake lines, and the pressure gauges strapped to a diver's wrist are all engineered around it. Because pressure grows without limit as depth grows, every one of those structures is designed against the load at its deepest point rather than against some average of the whole vessel.

Intuition usually goes wrong in the same place. Most people expect a wide lake to press harder than a narrow pipe filled to the same level, as if the sheer quantity of water mattered. The simulator settles the question: with Fluid Density at 1000 kg/m³ and the gauge parked at 4 m, the Gauge pressure readout holds at 39.24 kPa whether the Column Height slider sits at 6 m or at 15 m. Total volume never enters the formula.


The Physics Explained

The fluid column at rest with the depth gauge set to 4 m below the surface, before the simulation starts.

Imagine an imaginary vertical cylinder of liquid, cross-sectional area A, reaching from the free surface down to depth h. The liquid is at rest, so the upward force on the bottom face of that cylinder must exactly support the weight of everything above it. The weight is ρ · A · h · g, and dividing by the area A gives a pressure that is independent of A entirely: P = ρ · g · h. At the simulator's defaults of ρ = 1000 kg/m³ and h = 4 m, that evaluates to 1000 × 9.81 × 4 = 39 240 Pa, which the Gauge pressure readout reports as 39.24 kPa.

That figure is a gauge pressure, meaning it is measured relative to the air above the liquid. The atmosphere is already pressing down on the free surface with about 101 325 Pa, and that load is transmitted undiminished through the fluid. Adding it back gives the absolute pressure: 101 325 + 39 240 = 140 565 Pa, which the Abs. pressure readout shows as 140.6 kPa. Gauge pressure is what a tyre gauge or a dam designer works with; absolute pressure is what a decompression table or a boiling-point calculation needs.

Both density and depth enter the formula to the first power, so the response to either slider is strictly linear. Doubling Fluid Density from 1000 kg/m³ to 2000 kg/m³ at a fixed 4 m doubles the reading to 78 480 Pa (78.48 kPa). Doubling the depth instead, from 4 m to 8 m at 1000 kg/m³, produces exactly the same 78 480 Pa. And halving the density to 500 kg/m³ while holding 8 m of depth brings the reading back to 39 240 Pa, identical to the default. Only the product of density and depth matters, never the two values separately.

The right-hand panel plots this as a straight line running from zero at the surface down to ρ · g · H at the bottom of the column, where H is the Column Height. Its gradient is ρg, so a denser fluid tilts the line over more steeply while an emptier one flattens it. The pressure axis is deliberately fixed to the worst case the sliders allow, 2000 × 9.81 × 15 = 294 300 Pa (294.3 kPa), so the ghost profiles left by earlier runs stay directly comparable to the current one instead of being rescaled underfoot.


Key Equations

The pressure-vs-depth graph for salt water (1025 kg/m³) showing the steeper linear profile and the gauge dot at 6 m depth.
Gauge pressure at depth P = ρ · g · h

This is the whole of hydrostatics in one line. Substituting the defaults (ρ = 1000 kg/m³, g = 9.81 m/s², h = 4 m) gives 39 240 Pa, the 39.24 kPa the readout shows. The linearity is easy to test at the slider extremes: at the shallowest setting of 0.5 m the same fluid produces 4905 Pa (4.905 kPa), and at the deepest setting of 10 m it produces 98 100 Pa (98.1 kPa). The ratio of those two readings is exactly 20, because the ratio of the depths is exactly 20.

Absolute pressure Pabs = Patm + ρ · g · h

Absolute pressure counts from a perfect vacuum rather than from the local air, so the standard atmosphere of 101 325 Pa is added to the hydrostatic term. At 10 m in fresh water the sum is 101 325 + 98 100 = 199 425 Pa, which the Abs. pressure readout rounds to 199.4 kPa. That is very nearly two atmospheres, which is the origin of the diver's rule of thumb that every 10 m of water adds one more atmosphere of load.

Depth from a pressure reading h = P / (ρ · g)

Rearranged this way, the same relation becomes a measuring instrument. Feeding the default gauge reading of 39 240 Pa back through the inversion with ρ = 1000 kg/m³ gives 39 240 / (1000 × 9.81) = 4 m, recovering the Gauge Depth slider setting exactly. Every depth gauge, altimeter, and tank level sensor is doing this arithmetic internally, which is why each one has to be told what fluid it is sitting in.

Pressure difference between two levels ΔP = ρ · g · Δh

Because the profile is a straight line, only the vertical separation between two points matters, not their absolute depths. Density still scales the result: at 6 m the simulator reports 58 860 Pa (58.86 kPa) in fresh water at 1000 kg/m³, but 60 331.5 Pa (60.33 kPa) in sea water at 1025 kg/m³. The 1471.5 Pa gap between them is exactly 2.5 % of the fresh-water value, matching the 2.5 % density difference to the last digit.


Key Variables

Symbol Name Unit Meaning
PGauge pressurePa (kPa in readout)Pressure above the local atmosphere, produced by the fluid alone
PabsAbsolute pressurePa (kPa in readout)Pressure measured from a perfect vacuum; gauge pressure plus one atmosphere
PatmAtmospheric pressurePaStandard sea-level air pressure, fixed at 101 325 Pa in the simulator
ρFluid densitykg/m³Mass per unit volume of the liquid; 1000 kg/m³ for fresh water
gGravitational accelerationm/s²Surface gravity, 9.81 m/s²
hGauge depthmVertical distance from the free surface down to the gauge
HColumn heightmTotal depth of the fluid column; sets where the profile line ends

Real World Examples

After the gauge descends to 4 m in fresh water, pressure arrows appear and the readout shows 39.24 kPa gauge pressure.

Why is a dam wall thicker at the bottom than at the top?

A dam has to resist the water pressure acting on its upstream face, and that pressure is not uniform: it starts at zero at the reservoir surface and grows in direct proportion to depth. Near the top of the wall there is almost nothing to hold back, while at the base the full ρ · g · h load presses inward. Setting the simulator to Fluid Density 1000 kg/m³ with the gauge at 10 m of depth puts the Gauge pressure readout at 98.1 kPa, close to one full atmosphere pressing on every square metre of wall at that level. A designer therefore tapers the structure: thin where the load is small, massive where it is largest.

The right-hand panel shows why the taper follows a straight edge rather than a curve. Pressure rises linearly with depth, so the load diagram on the face of the wall is a triangle, zero at the waterline and maximal at the foot. The horizontal thrust the wall must carry is the area of that triangle, which grows with the square of the water depth, and its line of action sits one third of the way up from the base. Raising a reservoir by half again therefore more than doubles the overturning moment the foundation has to resist.

The simulator lets you watch the load diagram build. Set Column Height to 15 m and Gauge Depth to 10 m, press Start, and the crimson arrows on the column walls grow as the gauge descends, since their length tracks the local pressure. Leave the ghost profile from that run on the graph and repeat at 500 kg/m³ to see a gentler slope: dams holding lighter fluids, or reservoirs that are never filled to the crest, can be built appreciably slimmer.

How does a diver's depth gauge turn pressure into metres?

A depth gauge does not measure depth at all. It measures pressure and then inverts the hydrostatic relation, dividing the measured gauge pressure by ρ · g to recover a depth. Feeding the simulator's default reading of 39 240 Pa back through that inversion with ρ = 1000 kg/m³ returns exactly 4 m, the depth the Gauge Depth slider was set to. The arithmetic is only as good as the density the instrument assumes, which is why the same gauge reads slightly differently in fresh water and in the sea.

Set Fluid Density to 1025 kg/m³, the usual figure for sea water, and take the gauge down to 6 m. The readout climbs to 60.33 kPa, against 58.86 kPa for fresh water at the same 6 m. A gauge calibrated for fresh water fed that sea-water pressure would report about 6.15 m instead of 6 m, an error of 2.5 % that grows with every metre of descent and matters on a deep technical dive.

Decompression planning uses absolute pressure rather than gauge pressure, because it is the total pressure that drives nitrogen into solution in the blood. That is why the Abs. pressure readout matters: at 10 m in fresh water it reads 199.4 kPa, essentially double the surface value of 101.3 kPa. Doubling the ambient pressure roughly doubles the amount of gas the tissues can hold, which is the whole reason a slow ascent is not optional.

Why does the shape of a water tank not change the pressure at the tap?

Pressure in a still fluid is fixed by vertical depth below the free surface, not by how much fluid sits around or below the measuring point. A narrow standpipe and a broad reservoir filled to the same level deliver exactly the same pressure at the same depth. The simulator makes the point directly: hold Gauge Depth at 4 m in fresh water and sweep the Column Height slider from 6 m to 15 m, and the Gauge pressure readout stays pinned at 39.24 kPa for every column length. Adding fluid below the gauge adds weight to the container, but none of that extra weight rests on the layer being measured.

Municipal water systems are built on this fact. A water tower delivers pressure through height alone, so the tank on top can be modest in volume as long as it stands high enough. A tower whose water level sits 30 m above a street tap delivers 294 300 Pa (294.3 kPa) of gauge pressure there, close to three atmospheres, regardless of whether the tank holds a hundred cubic metres or a thousand. Volume buys reserve capacity; only height buys pressure.

The same reasoning explains the hydrostatic paradox, the eighteenth-century puzzle that the force on the base of a vessel can far exceed the weight of the liquid it holds. A tall, flaring vessel presses on its base with ρ · g · h times the base area no matter how little liquid the narrow neck contains, because the sloping walls carry the rest of the load. Pressure is a local statement about depth, and the container geometry is simply not part of the equation.


Further Reading